What is 9/2+3(4-1)-7+2^3 ?

The solution to 9/2+3(4-1)-7+2^3 is 14 1/2

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Popular Pre Algebra >

9/2+3(4-1)-7+2^3

Solution

\frac{9}{2} + 3 (4 - 1) - 7 + 2^{3}

Solution

14 \frac{1}{2}

Decimal

14.5

Solution steps

\frac{9}{2} + 3 (4 - 1) - 7 + 2^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 1) : 3

4 - 1

4 - 1 = 3

= 3

= \frac{9}{2} + 3 \cdot 3 - 7 + 2^{3}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= \frac{9}{2} + 3 \cdot 3 - 7 + 8

Multiply and divide (left to right)

3 \cdot 3 : 9

3 \cdot 3

3 \cdot 3 = 9

= 9

= \frac{9}{2} + 9 - 7 + 8

Add and subtract (left to right)

\frac{9}{2} + 9 - 7 + 8 : \frac{29}{2}

\frac{9}{2} + 9 - 7 + 8

\frac{9}{2} + 9 = \frac{27}{2}

\frac{9}{2} + 9

Convert element to fraction:

9 = \frac{9 \cdot 2}{2}

= \frac{9 \cdot 2}{2} + \frac{9}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{9 \cdot 2 + 9}{2}

9 \cdot 2 + 9 = 27

9 \cdot 2 + 9

Multiply the numbers:

9 \cdot 2 = 18

= 18 + 9

Add the numbers:

18 + 9 = 27

= 27

= \frac{27}{2}

= \frac{27}{2} - 7 + 8

\frac{27}{2} - 7 = \frac{13}{2}

\frac{27}{2} - 7

Convert element to fraction:

7 = \frac{7 \cdot 2}{2}

= - \frac{7 \cdot 2}{2} + \frac{27}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 7 \cdot 2 + 27}{2}

- 7 \cdot 2 + 27 = 13

- 7 \cdot 2 + 27

Multiply the numbers:

7 \cdot 2 = 14

= - 14 + 27

Add/Subtract the numbers:

- 14 + 27 = 13

= 13

= \frac{13}{2}

= \frac{13}{2} + 8

\frac{13}{2} + 8 = \frac{29}{2}

\frac{13}{2} + 8

Convert element to fraction:

8 = \frac{8 \cdot 2}{2}

= \frac{8 \cdot 2}{2} + \frac{13}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{8 \cdot 2 + 13}{2}

8 \cdot 2 + 13 = 29

8 \cdot 2 + 13

Multiply the numbers:

8 \cdot 2 = 16

= 16 + 13

Add the numbers:

16 + 13 = 29

= 29

= \frac{29}{2}

= \frac{29}{2}

= \frac{29}{2}

Convert improper fractions to mixed numbers:

\frac{29}{2} = 14 \frac{1}{2}

\frac{29}{2} = 14

Remainder

1

\frac{29}{2}

Write the problem in long division format

2 \overline{∣ 29}

Divide

2

2

to get

1

Divide

2

2

to get

1

1 2 \overline{∣ 29}

Multiply the quotient digit

(1)

by the divisor

2

1 2 \overline{∣ 29} \underline{2}

Subtract

2

from

2

1 2 \overline{∣ 29} \underline{2} 0

Bring down the next number of the dividend

1 2 \overline{∣ 29} \underline{2} 09

1 2 \overline{∣ 29} \underline{2} 09

Divide

9

2

to get

4

Divide

9

2

to get

4

14 2 \overline{∣ 29} \underline{2} 09

Multiply the quotient digit

(4)

by the divisor

2

14 2 \overline{∣ 29} \underline{2} 09 \underline{8}

Subtract

8

from

9

14 2 \overline{∣ 29} \underline{2} 09 \underline{8} 1

14 2 \overline{∣ 29} \underline{2} 09 \underline{8} 1

The solution for Long Division of

\frac{29}{2}

14

with remainder of

1

14 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{29}{2} = 14 \frac{1}{2}

= 14 \frac{1}{2}

= 14 \frac{1}{2}

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Frequently Asked Questions (FAQ)

What is 9/2+3(4-1)-7+2^3 ?
The solution to 9/2+3(4-1)-7+2^3 is 14 1/2

9/2+3(4-1)-7+2^3

Solution

Solution

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Frequently Asked Questions (FAQ)

What is 9/2+3(4-1)-7+2^3 ?

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