What is -3[4(150\div 5^3-2-7-20)]-80 ?

The solution to -3[4(150\div 5^3-2-7-20)]-80 is 253 3/5

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Popular Pre Algebra >

-3[4(150\div 5^3-2-7-20)]-80

Solution

- 3 [4 (150 \div 5^{3} - 2 - 7 - 20)] - 80

Solution

253 \frac{3}{5}

Decimal

253.6

Solution steps

- 3 [4 (150 \div 5^{3} - 2 - 7 - 20)] - 80

Follow the PEMDAS order of operations

Calculate within parentheses

[4 (150 \div 5^{3} - 2 - 7 - 20)] : - \frac{556}{5}

4 (150 \div 5^{3} - 2 - 7 - 20)

Calculate within parentheses

(150 \div 5^{3} - 2 - 7 - 20) : - \frac{139}{5}

150 \div 5^{3} - 2 - 7 - 20

Calculate exponents

5^{3} : 125

5^{3}

5^{3} = 125

= 125

= 150 \div 125 - 2 - 7 - 20

Multiply and divide (left to right)

150 \div 125 : \frac{150}{125}

150 \div 125

150 \div 125 = \frac{150}{125}

= \frac{150}{125}

= \frac{150}{125} - 2 - 7 - 20

Add and subtract (left to right)

\frac{150}{125} - 2 - 7 - 20 : - \frac{139}{5}

\frac{150}{125} - 2 - 7 - 20

\frac{150}{125} - 2 = - \frac{4}{5}

\frac{150}{125} - 2

Cancel

\frac{150}{125} : \frac{6}{5}

\frac{150}{125}

Cancel the common factor:

25

= \frac{6}{5}

= \frac{6}{5} - 2

Convert element to fraction:

2 = \frac{2 \cdot 5}{5}

= - \frac{2 \cdot 5}{5} + \frac{6}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 5 + 6}{5}

- 2 \cdot 5 + 6 = - 4

- 2 \cdot 5 + 6

Multiply the numbers:

2 \cdot 5 = 10

= - 10 + 6

Add/Subtract the numbers:

- 10 + 6 = - 4

= - 4

= \frac{- 4}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{5}

= - \frac{4}{5} - 7 - 20

- \frac{4}{5} - 7 = - \frac{39}{5}

- \frac{4}{5} - 7

Convert element to fraction:

7 = \frac{7 \cdot 5}{5}

= - \frac{7 \cdot 5}{5} - \frac{4}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 7 \cdot 5 - 4}{5}

- 7 \cdot 5 - 4 = - 39

- 7 \cdot 5 - 4

Multiply the numbers:

7 \cdot 5 = 35

= - 35 - 4

Subtract the numbers:

- 35 - 4 = - 39

= - 39

= \frac{- 39}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{39}{5}

= - \frac{39}{5} - 20

- \frac{39}{5} - 20 = - \frac{139}{5}

- \frac{39}{5} - 20

Convert element to fraction:

20 = \frac{20 \cdot 5}{5}

= - \frac{20 \cdot 5}{5} - \frac{39}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 20 \cdot 5 - 39}{5}

- 20 \cdot 5 - 39 = - 139

- 20 \cdot 5 - 39

Multiply the numbers:

20 \cdot 5 = 100

= - 100 - 39

Subtract the numbers:

- 100 - 39 = - 139

= - 139

= \frac{- 139}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{139}{5}

= - \frac{139}{5}

= - \frac{139}{5}

= 4 (- \frac{139}{5})

Multiply and divide (left to right)

4 (- \frac{139}{5}) : - \frac{556}{5}

4 (- \frac{139}{5})

Apply rule

a \cdot (- b) = - a \cdot b

4 (- \frac{139}{5}) = - 4 \cdot \frac{139}{5}

Convert element to fraction:

4 = \frac{4}{1}

= - \frac{4}{1} \cdot \frac{139}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{4}{1} \cdot \frac{139}{5} = \frac{4 \cdot 139}{1 \cdot 5}

= - \frac{4 \cdot 139}{1 \cdot 5}

Multiply the numbers:

4 \cdot 139 = 556

= - \frac{556}{1 \cdot 5}

Multiply the numbers:

1 \cdot 5 = 5

= - \frac{556}{5}

= - \frac{556}{5}

= - 3 (- \frac{556}{5}) - 80

Multiply and divide (left to right)

- 3 (- \frac{556}{5}) : \frac{1668}{5}

- 3 (- \frac{556}{5})

Apply rule

- a \cdot (- b) = a \cdot b

- 3 (- \frac{556}{5}) = 3 \cdot \frac{556}{5}

Convert element to fraction:

3 = \frac{3}{1}

= \frac{3}{1} \cdot \frac{556}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 556}{1 \cdot 5}

Multiply the numbers:

3 \cdot 556 = 1668

= \frac{1668}{1 \cdot 5}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{1668}{5}

= \frac{1668}{5} - 80

Add and subtract (left to right)

\frac{1668}{5} - 80 : \frac{1268}{5}

\frac{1668}{5} - 80

\frac{1668}{5} - 80 = \frac{1268}{5}

\frac{1668}{5} - 80

Convert element to fraction:

80 = \frac{80 \cdot 5}{5}

= - \frac{80 \cdot 5}{5} + \frac{1668}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 80 \cdot 5 + 1668}{5}

- 80 \cdot 5 + 1668 = 1268

- 80 \cdot 5 + 1668

Multiply the numbers:

80 \cdot 5 = 400

= - 400 + 1668

Add/Subtract the numbers:

- 400 + 1668 = 1268

= 1268

= \frac{1268}{5}

= \frac{1268}{5}

= \frac{1268}{5}

Convert improper fractions to mixed numbers:

\frac{1268}{5} = 253 \frac{3}{5}

\frac{1268}{5} = 253

Remainder

3

\frac{1268}{5}

Write the problem in long division format

5 \overline{∣ 1268}

Divide

12

5

to get

2

Divide

12

5

to get

2

2 5 \overline{∣ 1268}

Multiply the quotient digit

(2)

by the divisor

5

2 5 \overline{∣ 1268} \underline{10}

Subtract

10

from

12

2 5 \overline{∣ 1268} \underline{10} 2

Bring down the next number of the dividend

2 5 \overline{∣ 1268} \underline{10} 26

2 5 \overline{∣ 1268} \underline{10} 26

Divide

26

5

to get

5

Divide

26

5

to get

5

25 5 \overline{∣ 1268} \underline{10} 26

Multiply the quotient digit

(5)

by the divisor

5

25 5 \overline{∣ 1268} \underline{10} 26 \underline{25}

Subtract

25

from

26

25 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 1

Bring down the next number of the dividend

25 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 18

25 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 18

Divide

18

5

to get

3

Divide

18

5

to get

3

253 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 18

Multiply the quotient digit

(3)

by the divisor

5

253 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 18 \underline{15}

Subtract

15

from

18

253 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 18 \underline{15} 3

253 5 \overline{∣ 1268} \underline{10} 26 \underline{25} 18 \underline{15} 3

The solution for Long Division of

\frac{1268}{5}

253

with remainder of

3

253 Remainder 3

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{1268}{5} = 253 \frac{3}{5}

= 253 \frac{3}{5}

= 253 \frac{3}{5}

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Frequently Asked Questions (FAQ)

What is -3[4(150\div 5^3-2-7-20)]-80 ?
The solution to -3[4(150\div 5^3-2-7-20)]-80 is 253 3/5

-3[4(150\div 5^3-2-7-20)]-80

Solution

Solution

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Frequently Asked Questions (FAQ)

What is -3[4(150\div 5^3-2-7-20)]-80 ?

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