What is (-2)^4+(+5)\times (2) ?

The solution to (-2)^4+(+5)\times (2) is 26

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(-2)^4+(+5)\times (2)

(- 2)^{4} + (+ 5) \cdot (2)

26

Solution steps

(- 2)^{4} + (5) (2)

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= 16 + (5) (2)

Multiply and divide (left to right)

(5) (2) : 10

(5) (2)

(5) (2) = 5 \cdot 2

(5) (2)

Apply rule:

(a) = a

(5) = 5

= 5 (2)

Apply rule:

(a) = a

(2) = 2

= 5 \cdot 2

= 5 \cdot 2

Multiply the numbers:

5 \cdot 2 = 10

= 10

= 16 + 10

Add and subtract (left to right)

16 + 10 : 26

16 + 10

16 + 10 = 26

= 26

= 26

6 - 2 + 10 \div 5

(- 2)^{2} - 8

- 15 - 36 \cdot (- \frac{4}{9})

7 (4)^{2}

10 (- 3)^{2} + 8 (- 3)