What is (2+1)/(2^2+2) ?

The solution to (2+1)/(2^2+2) is 1/2

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(2+1)/(2^2+2)

\frac{2 + 1}{2 ^{2} + 2}

\frac{1}{2}

Solution steps

\frac{2 + 1}{2 ^{2} + 2}

Solve

2 + 1 : 3

2 + 1 = 3

= 3

Solve

2^{2} + 2 : 6

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 + 2

Add and subtract (left to right)

4 + 2 : 6

4 + 2

4 + 2 = 6

= 6

= 6

= \frac{3}{6}

Cancel the common factor:

3

= \frac{1}{2}

1 + 3 \cdot \frac{2}{5}

3 (- 5)^{2} - 3 (- 5)

3 (2)^{2} - 12 (2) + 9

35 \times (12 \div 6) - 52 + (32 \div 8) - 9

- [3 + 5 - (4 - 6) + 3]