What is 7^2-(-5)^0+[(2)^4+(-2)^3-2^1] ?

The solution to 7^2-(-5)^0+[(2)^4+(-2)^3-2^1] is 54

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7^2-(-5)^0+[(2)^4+(-2)^3-2^1]

7^{2} - (- 5)^{0} + [(2)^{4} + (- 2)^{3} - 2^{1}]

54

Solution steps

7^{2} - (- 5)^{0} + [(2)^{4} + (- 2)^{3} - 2^{1}]

Follow the PEMDAS order of operations

Calculate within parentheses

[(2)^{4} + (- 2)^{3} - 2^{1}] : 6

(2)^{4} + (- 2)^{3} - 2^{1}

Calculate exponents

(2)^{4} : 16

(2)^{4}

(2)^{4} = 16

= 16

= 16 + (- 2)^{3} - 2^{1}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 16 - 8 - 2^{1}

Calculate exponents

2^{1} : 2

2^{1}

2^{1} = 2

= 2

= 16 - 8 - 2^{1}

Add and subtract (left to right)

16 - 8 - 2^{1} : 6

16 - 8 - 2^{1}

16 - 8 = 8

= 8 - 2^{1}

8 - 2^{1} = 6

= 6

= 6

= 7^{2} - (- 5)^{0} + 6

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 49 - (- 5)^{0} + 6

Calculate exponents

(- 5)^{0} : 1

(- 5)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{0} = 5^{0} = 1

= 1

= 49 - 1 + 6

Add and subtract (left to right)

49 - 1 + 6 : 54

49 - 1 + 6

49 - 1 = 48

= 48 + 6

48 + 6 = 54

= 54

= 54

\frac{7}{6} - (\frac{5}{6} - \frac{1}{6})

3^{2} + 1^{2}

6 (6 + 9 + 15) - 8 (2 + 7 - 3)

180 (8 - 2)

2^{5} \cdot 2

What is 7^2-(-5)^0+[(2)^4+(-2)^3-2^1] ?
The solution to 7^2-(-5)^0+[(2)^4+(-2)^3-2^1] is 54