What is 1/4 (6+3+1)^2 ?

The solution to 1/4 (6+3+1)^2 is 25

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1/4 (6+3+1)^2

\frac{1}{4} (6 + 3 + 1)^{2}

25

Solution steps

\frac{1}{4} (6 + 3 + 1)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(6 + 3 + 1) : 10

6 + 3 + 1

6 + 3 + 1 = 10

= 10

= \frac{1}{4} \cdot 1 0^{2}

Calculate exponents

1 0^{2} : 100

1 0^{2}

1 0^{2} = 100

= 100

= \frac{1}{4} \cdot 100

Multiply and divide (left to right)

\frac{1}{4} \cdot 100 : 25

\frac{1}{4} \cdot 100

Convert element to fraction:

100 = \frac{100}{1}

= \frac{1}{4} \cdot \frac{100}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 100}{4 \cdot 1}

\frac{1 \cdot 100}{4 \cdot 1} = 25

\frac{1 \cdot 100}{4 \cdot 1}

\frac{1 \cdot 100}{4 \cdot 1} = \frac{100}{4}

\frac{1 \cdot 100}{4 \cdot 1}

Multiply the numbers:

1 \cdot 100 = 100

= \frac{100}{4 \cdot 1}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{100}{4}

= \frac{100}{4}

Divide the numbers:

\frac{100}{4} = 25

= 25

= 25

= 25

5 (3) + (- 7) (- 2)^{2}

5 (- 1 (7 + 12 - 16) + 4) + 2

(- 12) \times (- 14) \div (- 3)

(5 \cdot 2 \cdot 3)^{4}

2 5^{2} - 2 0^{2}