What is 79-15/8-27/10 ?

The solution to 79-15/8-27/10 is 74 17/40

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Popular Pre Algebra >

79-15/8-27/10

Solution

79 - \frac{15}{8} - \frac{27}{10}

Solution

74 \frac{17}{40}

Decimal

74.425

Solution steps

79 - \frac{15}{8} - \frac{27}{10}

Follow the PEMDAS order of operations

Add and subtract (left to right)

79 - \frac{15}{8} = \frac{617}{8}

79 - \frac{15}{8}

Convert element to fraction:

79 = \frac{79 \cdot 8}{8}

= \frac{79 \cdot 8}{8} - \frac{15}{8}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{79 \cdot 8 - 15}{8}

79 \cdot 8 - 15 = 617

79 \cdot 8 - 15

Multiply the numbers:

79 \cdot 8 = 632

= 632 - 15

Subtract the numbers:

632 - 15 = 617

= 617

= \frac{617}{8}

= \frac{617}{8} - \frac{27}{10}

\frac{617}{8} - \frac{27}{10} = \frac{2977}{40}

\frac{617}{8} - \frac{27}{10}

Least Common Multiplier of

8, 10 : 40

8, 10

Least Common Multiplier (LCM)

Prime factorization of

8 : 2 \cdot 2 \cdot 2

8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2

Prime factorization of

10 : 2 \cdot 5

10

10

divides by

210 = 5 \cdot 2

= 2 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 5

Multiply each factor the greatest number of times it occurs in either

8

10

= 2 \cdot 2 \cdot 2 \cdot 5

Multiply the numbers:

2 \cdot 2 \cdot 2 \cdot 5 = 40

= 40

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

40

For

\frac{617}{8} :

multiply the denominator and numerator by

5

\frac{617}{8} = \frac{617 \cdot 5}{8 \cdot 5} = \frac{3085}{40}

For

\frac{27}{10} :

multiply the denominator and numerator by

4

\frac{27}{10} = \frac{27 \cdot 4}{10 \cdot 4} = \frac{108}{40}

= \frac{3085}{40} - \frac{108}{40}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3085 - 108}{40}

Subtract the numbers:

3085 - 108 = 2977

= \frac{2977}{40}

= \frac{2977}{40}

Convert improper fractions to mixed numbers:

\frac{2977}{40} = 74 \frac{17}{40}

\frac{2977}{40} = 74

Remainder

17

\frac{2977}{40}

Write the problem in long division format

40 \overline{∣ 2977}

Divide

297

40

to get

7

Divide

297

40

to get

7

7 40 \overline{∣ 2977}

Multiply the quotient digit

(7)

by the divisor

40

7 40 \overline{∣ 2977} \underline{280}

Subtract

280

from

297

7 40 \overline{∣ 2977} \underline{280} 17

Bring down the next number of the dividend

7 40 \overline{∣ 2977} \underline{280} 177

7 40 \overline{∣ 2977} \underline{280} 177

Divide

177

40

to get

4

Divide

177

40

to get

4

74 40 \overline{∣ 2977} \underline{280} 177

Multiply the quotient digit

(4)

by the divisor

40

74 40 \overline{∣ 2977} \underline{280} 177 \underline{160}

Subtract

160

from

177

74 40 \overline{∣ 2977} \underline{280} 177 \underline{160} 17

74 40 \overline{∣ 2977} \underline{280} 177 \underline{160} 17

The solution for Long Division of

\frac{2977}{40}

74

with remainder of

17

74 Remainder 17

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{2977}{40} = 74 \frac{17}{40}

= 74 \frac{17}{40}

= 74 \frac{17}{40}

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What is 79-15/8-27/10 ?
The solution to 79-15/8-27/10 is 74 17/40

79-15/8-27/10

Solution

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What is 79-15/8-27/10 ?

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