zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的初等代数 >

(1-2/5)\div (2-1/2)

解答

(1 - \frac{2}{5}) \div (2 - \frac{1}{2})

解答

\frac{2}{5}

+1

十进制

0.4

求解步骤

(1 - \frac{2}{5}) \div (2 - \frac{1}{2})

遵循 PEMDAS 运算顺序

计算括号内的值

(1 - \frac{2}{5}) : \frac{3}{5}

1 - \frac{2}{5}

1 - \frac{2}{5} = \frac{3}{5}

1 - \frac{2}{5}

将项转换为分式:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{2}{5}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 2}{5}

1 \cdot 5 - 2 = 3

1 \cdot 5 - 2

数字相乘:

1 \cdot 5 = 5

= 5 - 2

数字相减:

5 - 2 = 3

= 3

= \frac{3}{5}

= \frac{3}{5}

= \frac{3}{5} \div (2 - \frac{1}{2})

计算括号内的值

(2 - \frac{1}{2}) : \frac{3}{2}

2 - \frac{1}{2}

2 - \frac{1}{2} = \frac{3}{2}

2 - \frac{1}{2}

将项转换为分式:

2 = \frac{2 \cdot 2}{2}

= \frac{2 \cdot 2}{2} - \frac{1}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 2 - 1}{2}

2 \cdot 2 - 1 = 3

2 \cdot 2 - 1

数字相乘:

2 \cdot 2 = 4

= 4 - 1

数字相减:

4 - 1 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= \frac{3}{5} \div \frac{3}{2}

乘除（左右）

\frac{3}{5} \div \frac{3}{2} : \frac{2}{5}

\frac{3}{5} \div \frac{3}{2}

使用分式法则:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{3}{5} \cdot \frac{2}{3}

交叉约分:

3

= \frac{2}{5}

= \frac{2}{5}

流行的例子

((-3)^3)/((-3)^2)

\frac{( - 3 ) ^{3}}{( - 3 ) ^{2}}

3 (1 - 1) + 3

化简 3/4-4/12

s im pl i f y \frac{3}{4} - \frac{4}{12}

3+[4-3(9-2)+21]

3 + [4 - 3 (9 - 2) + 21]

0 - (1 \times (- \frac{1}{2}))