What is 7+1/10-33/100 ?

The solution to 7+1/10-33/100 is 6 77/100

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Popular Pre Algebra >

7+1/10-33/100

Solution

7 + \frac{1}{10} - \frac{33}{100}

Solution

6 \frac{77}{100}

Decimal

6.77

Solution steps

7 + \frac{1}{10} - \frac{33}{100}

Follow the PEMDAS order of operations

Add and subtract (left to right)

7 + \frac{1}{10} = \frac{71}{10}

7 + \frac{1}{10}

Convert element to fraction:

7 = \frac{7 \cdot 10}{10}

= \frac{7 \cdot 10}{10} + \frac{1}{10}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 \cdot 10 + 1}{10}

7 \cdot 10 + 1 = 71

7 \cdot 10 + 1

Multiply the numbers:

7 \cdot 10 = 70

= 70 + 1

Add the numbers:

70 + 1 = 71

= 71

= \frac{71}{10}

= \frac{71}{10} - \frac{33}{100}

\frac{71}{10} - \frac{33}{100} = \frac{677}{100}

\frac{71}{10} - \frac{33}{100}

Least Common Multiplier of

10, 100 : 100

10, 100

Least Common Multiplier (LCM)

Prime factorization of

10 : 2 \cdot 5

10

10

divides by

210 = 5 \cdot 2

= 2 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 5

Prime factorization of

100 : 2 \cdot 2 \cdot 5 \cdot 5

100

100

divides by

2100 = 50 \cdot 2

= 2 \cdot 50

50

divides by

250 = 25 \cdot 2

= 2 \cdot 2 \cdot 25

25

divides by

525 = 5 \cdot 5

= 2 \cdot 2 \cdot 5 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 5 \cdot 5

Multiply each factor the greatest number of times it occurs in either

10

100

= 2 \cdot 2 \cdot 5 \cdot 5

Multiply the numbers:

2 \cdot 2 \cdot 5 \cdot 5 = 100

= 100

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

100

For

\frac{71}{10} :

multiply the denominator and numerator by

10

\frac{71}{10} = \frac{71 \cdot 10}{10 \cdot 10} = \frac{710}{100}

= \frac{710}{100} - \frac{33}{100}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{710 - 33}{100}

Subtract the numbers:

710 - 33 = 677

= \frac{677}{100}

= \frac{677}{100}

Convert improper fractions to mixed numbers:

\frac{677}{100} = 6 \frac{77}{100}

\frac{677}{100} = 6

Remainder

77

\frac{677}{100}

Write the problem in long division format

100 \overline{∣ 677}

Divide

677

100

to get

6

Divide

677

100

to get

6

6 100 \overline{∣ 677}

Multiply the quotient digit

(6)

by the divisor

100

6 100 \overline{∣ 677} \underline{600}

Subtract

600

from

677

6 100 \overline{∣ 677} \underline{600} 77

6 100 \overline{∣ 677} \underline{600} 77

The solution for Long Division of

\frac{677}{100}

6

with remainder of

77

6 Remainder 77

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{677}{100} = 6 \frac{77}{100}

= 6 \frac{77}{100}

= 6 \frac{77}{100}

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Frequently Asked Questions (FAQ)

What is 7+1/10-33/100 ?
The solution to 7+1/10-33/100 is 6 77/100

7+1/10-33/100

Solution

Solution

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What is 7+1/10-33/100 ?

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