What is [5(3-4)/2]/3+[2(3+3(2-1))]^3 ?

The solution to [5(3-4)/2]/3+[2(3+3(2-1))]^3 is 1727 1/6

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Popular Pre Algebra >

[5(3-4)/2]/3+[2(3+3(2-1))]^3

Solution

[5 (3 - 4) /2] /3 + [2 (3 + 3 (2 - 1))]^{3}

Solution

1727 \frac{1}{6}

Decimal

1727.16666 \dots

Solution steps

[5 (3 - 4) /2] /3 + [2 (3 + 3 (2 - 1))]^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

[5 (3 - 4) /2] : \frac{- 5}{2}

5 (3 - 4) /2

Calculate within parentheses

(3 - 4) : - 1

3 - 4

3 - 4 = - 1

= - 1

= 5 (- 1) /2

Multiply and divide (left to right)

5 (- 1) /2 : \frac{- 5}{2}

5 (- 1) /2

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 1) = - 5 \cdot 1 = - 5

= - 5/2

- 5/2 = \frac{- 5}{2}

= \frac{- 5}{2}

= \frac{- 5}{2}

= \frac{- 5}{2} /3 + [2 (3 + 3 (2 - 1))]^{3}

Calculate within parentheses

[2 (3 + 3 (2 - 1))] : 12

2 (3 + 3 (2 - 1))

Calculate within parentheses

(3 + 3 (2 - 1)) : 6

3 + 3 (2 - 1)

Calculate within parentheses

(2 - 1) : 1

2 - 1

2 - 1 = 1

= 1

= 3 + 3 \cdot 1

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 + 3

Add and subtract (left to right)

3 + 3 : 6

3 + 3

3 + 3 = 6

= 6

= 6

= 2 \cdot 6

Multiply and divide (left to right)

2 \cdot 6 : 12

2 \cdot 6

2 \cdot 6 = 12

= 12

= 12

= \frac{- 5}{2} /3 + 1 2^{3}

Calculate exponents

1 2^{3} : 1728

1 2^{3}

1 2^{3} = 1728

= 1728

= \frac{- 5}{2} /3 + 1728

Multiply and divide (left to right)

\frac{- 5}{2} /3 : - \frac{5}{6}

\frac{- 5}{2} /3

Convert element to fraction:

3 = \frac{3}{1}

= \frac{- 5}{2} \div \frac{3}{1}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{- 5}{2} \cdot \frac{1}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{5}{2} \cdot \frac{1}{3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{5 \cdot 1}{2 \cdot 3}

Multiply the numbers:

5 \cdot 1 = 5

= - \frac{5}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= - \frac{5}{6}

= - \frac{5}{6} + 1728

Add and subtract (left to right)

- \frac{5}{6} + 1728 : \frac{10363}{6}

- \frac{5}{6} + 1728

- \frac{5}{6} + 1728 = \frac{10363}{6}

- \frac{5}{6} + 1728

Convert element to fraction:

1728 = \frac{1728 \cdot 6}{6}

= \frac{1728 \cdot 6}{6} - \frac{5}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1728 \cdot 6 - 5}{6}

1728 \cdot 6 - 5 = 10363

1728 \cdot 6 - 5

Multiply the numbers:

1728 \cdot 6 = 10368

= 10368 - 5

Subtract the numbers:

10368 - 5 = 10363

= 10363

= \frac{10363}{6}

= \frac{10363}{6}

= \frac{10363}{6}

Convert improper fractions to mixed numbers:

\frac{10363}{6} = 1727 \frac{1}{6}

\frac{10363}{6} = 1727

Remainder

1

\frac{10363}{6}

Write the problem in long division format

6 \overline{∣ 10363}

Divide

10

6

to get

1

Divide

10

6

to get

1

1 6 \overline{∣ 10363}

Multiply the quotient digit

(1)

by the divisor

6

1 6 \overline{∣ 10363} \underline{6}

Subtract

6

from

10

1 6 \overline{∣ 10363} \underline{6} 4

Bring down the next number of the dividend

1 6 \overline{∣ 10363} \underline{6} 43

1 6 \overline{∣ 10363} \underline{6} 43

Divide

43

6

to get

7

Divide

43

6

to get

7

17 6 \overline{∣ 10363} \underline{6} 43

Multiply the quotient digit

(7)

by the divisor

6

17 6 \overline{∣ 10363} \underline{6} 43 \underline{42}

Subtract

42

from

43

17 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 1

Bring down the next number of the dividend

17 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16

17 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16

Divide

16

6

to get

2

Divide

16

6

to get

2

172 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16

Multiply the quotient digit

(2)

by the divisor

6

172 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12}

Subtract

12

from

16

172 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 4

Bring down the next number of the dividend

172 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 43

172 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 43

Divide

43

6

to get

7

Divide

43

6

to get

7

1727 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 43

Multiply the quotient digit

(7)

by the divisor

6

1727 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 43 \underline{42}

Subtract

42

from

43

1727 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 43 \underline{42} 1

1727 6 \overline{∣ 10363} \underline{6} 43 \underline{42} 16 \underline{12} 43 \underline{42} 1

The solution for Long Division of

\frac{10363}{6}

1727

with remainder of

1

1727 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{10363}{6} = 1727 \frac{1}{6}

= 1727 \frac{1}{6}

= 1727 \frac{1}{6}

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Frequently Asked Questions (FAQ)

What is [5(3-4)/2]/3+[2(3+3(2-1))]^3 ?
The solution to [5(3-4)/2]/3+[2(3+3(2-1))]^3 is 1727 1/6

[5(3-4)/2]/3+[2(3+3(2-1))]^3

Solution

Solution

Popular Examples

Frequently Asked Questions (FAQ)

What is [5(3-4)/2]/3+[2(3+3(2-1))]^3 ?

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