What is 4(-2)^2-3(-2)-16 ?

The solution to 4(-2)^2-3(-2)-16 is 6

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4(-2)^2-3(-2)-16

4 (- 2)^{2} - 3 (- 2) - 16

6

Solution steps

4 (- 2)^{2} - 3 (- 2) - 16

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 \cdot 4 - 3 (- 2) - 16

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 16 - 3 (- 2) - 16

Multiply and divide (left to right)

3 (- 2) : - 6

3 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 2) = - 3 \cdot 2 = - 6

= - 6

= 16 - (- 6) - 16

Add and subtract (left to right)

16 - (- 6) - 16 : 6

16 - (- 6) - 16

Apply rule

- (- a) = + a

- (- 6) = + 6

= 16 + 6 - 16

16 + 6 = 22

= 22 - 16

22 - 16 = 6

= 6

= 6

- 3 - (- 2) \times 4 + 20 \div (- 4) + (- 1)

6 \times 6^{3}

- [- 4 + 2 - (- 10)] - [(- 10) + (10)]

2 4^{2} + 1 9^{2}

6 - 2 [4 - 8 + [- 5 + 3 (- 1 + 7 - 6)]]