What is ((2)^2-5)^2+9 ?

The solution to ((2)^2-5)^2+9 is 10

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((2)^2-5)^2+9

((2)^{2} - 5)^{2} + 9

10

Solution steps

((2)^{2} - 5)^{2} + 9

Follow the PEMDAS order of operations

Calculate within parentheses

((2)^{2} - 5) : - 1

(2)^{2} - 5

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 4 - 5

Add and subtract (left to right)

4 - 5 : - 1

4 - 5

4 - 5 = - 1

= - 1

= - 1

= (- 1)^{2} + 9

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 + 9

Add and subtract (left to right)

1 + 9 : 10

1 + 9

1 + 9 = 10

= 10

= 10

2^{8} - 10 - 15 \div 3

6 (- 2)^{2}

6 + 11 \times 2 + 8

4 (2) - 2

\frac{2}{3} + (- \frac{1}{8} + \frac{3}{4})