What is (5/3-1)\times (7/2-2) ?

The solution to (5/3-1)\times (7/2-2) is 1

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(5/3-1)\times (7/2-2)

(\frac{5}{3} - 1) \cdot (\frac{7}{2} - 2)

1

Solution steps

(\frac{5}{3} - 1) (\frac{7}{2} - 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{5}{3} - 1) : \frac{2}{3}

\frac{5}{3} - 1

\frac{5}{3} - 1 = \frac{2}{3}

\frac{5}{3} - 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= - \frac{1 \cdot 3}{3} + \frac{5}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 3 + 5}{3}

- 1 \cdot 3 + 5 = 2

- 1 \cdot 3 + 5

Multiply the numbers:

1 \cdot 3 = 3

= - 3 + 5

Add/Subtract the numbers:

- 3 + 5 = 2

= 2

= \frac{2}{3}

= \frac{2}{3}

= \frac{2}{3} (\frac{7}{2} - 2)

Calculate within parentheses

(\frac{7}{2} - 2) : \frac{3}{2}

\frac{7}{2} - 2

\frac{7}{2} - 2 = \frac{3}{2}

\frac{7}{2} - 2

Convert element to fraction:

2 = \frac{2 \cdot 2}{2}

= - \frac{2 \cdot 2}{2} + \frac{7}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 2 + 7}{2}

- 2 \cdot 2 + 7 = 3

- 2 \cdot 2 + 7

Multiply the numbers:

2 \cdot 2 = 4

= - 4 + 7

Add/Subtract the numbers:

- 4 + 7 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= \frac{2}{3} \cdot \frac{3}{2}

Multiply and divide (left to right)

\frac{2}{3} \cdot \frac{3}{2} : 1

\frac{2}{3} \cdot \frac{3}{2}

\frac{2}{3} \cdot \frac{3}{2} = 1

= 1

= 1

2 4^{2} + 3 2^{2}

9^{2} + 6^{2}

180 (5 - 2)

- 3 - 4 \cdot 10 \div 2 \cdot 4 - 5

0 - (1 \times 0)