What is 4(-4)^2+3(-4) ?

The solution to 4(-4)^2+3(-4) is 52

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4(-4)^2+3(-4)

4 (- 4)^{2} + 3 (- 4)

52

Solution steps

4 (- 4)^{2} + 3 (- 4)

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 4 \cdot 16 + 3 (- 4)

Multiply and divide (left to right)

4 \cdot 16 : 64

4 \cdot 16

4 \cdot 16 = 64

= 64

= 64 + 3 (- 4)

Multiply and divide (left to right)

3 (- 4) : - 12

3 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 4) = - 3 \cdot 4 = - 12

= - 12

= 64 - 12

Add and subtract (left to right)

64 - 12 : 52

64 - 12

64 - 12 = 52

= 52

= 52

10 \times (5 + 3 + 7) - (6 + 2)^{2}

(- 2 + 3 - 1) \div (- 3 + 2)

(- 4) - (- 3) + (+ 2) - (+ 1) + (- 8)

(7 + 3 \frac{1}{8}) \div (14 + 6 \frac{1}{4})

- 24 + 36 \div (- 6) \times 2 - 12