What is -2^3-3(-2)^2 ?

The solution to -2^3-3(-2)^2 is -20

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-2^3-3(-2)^2

- 2^{3} - 3 (- 2)^{2}

- 20

Solution steps

- 2^{3} - 3 (- 2)^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= - 8 - 3 (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 8 - 3 \cdot 4

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= - 8 - 12

Add and subtract (left to right)

- 8 - 12 : - 20

- 8 - 12

- 8 - 12 = - 20

= - 20

= - 20

16 \times 3 + 7 \div 7 - 13 \times 9

2 \div 3 \div 4 \div 5 \div 6 \div 8

- 10 \cdot 1 2^{2}

(3 (- 20 + 8)) \div (1 - 2 \times 5)

- (- 2)^{2} - 4