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Popular Pre Algebra >

1× (1\div 2)-(1\div 2)\div 1000

  • Pre Algebra
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Solution

1×(1÷2)−(1÷2)÷1000

Solution

2000999​
+1
Decimal
0.4995
Solution steps
1×(1÷2)−(1÷2)÷1000
Follow the PEMDAS order of operations
Calculate within parentheses (1÷2):21​
1÷2
1÷2=21​=21​
=1×21​−(1÷2)÷1000
Calculate within parentheses (1÷2):21​
1÷2
1÷2=21​=21​
=1×21​−21​÷1000
Multiply and divide (left to right) 1×21​:21​
1×21​
1×21​=21​=21​
=21​−21​÷1000
Multiply and divide (left to right) 21​÷1000:20001​
21​÷1000
Convert element to fraction: 1000=11000​=21​÷11000​
Apply the fraction rule: ba​÷dc​=ba​×cd​=21​⋅10001​
Multiply fractions: ba​⋅dc​=b⋅da⋅c​=2⋅10001⋅1​
Multiply the numbers: 1⋅1=1=2⋅10001​
Multiply the numbers: 2⋅1000=2000=20001​
=21​−20001​
Add and subtract (left to right) 21​−20001​:2000999​
21​−20001​
21​−20001​=2000999​
21​−20001​
Least Common Multiplier of 2,2000:2000
2,2000
Least Common Multiplier (LCM)
Prime factorization of 2:2
2
2 is a prime number, therefore no factorization is possible=2
Prime factorization of 2000:2⋅2⋅2⋅2⋅5⋅5⋅5
2000
2000divides by 22000=1000⋅2=2⋅1000
1000divides by 21000=500⋅2=2⋅2⋅500
500divides by 2500=250⋅2=2⋅2⋅2⋅250
250divides by 2250=125⋅2=2⋅2⋅2⋅2⋅125
125divides by 5125=25⋅5=2⋅2⋅2⋅2⋅5⋅25
25divides by 525=5⋅5=2⋅2⋅2⋅2⋅5⋅5⋅5
2,5 are all prime numbers, therefore no further factorization is possible=2⋅2⋅2⋅2⋅5⋅5⋅5
Multiply each factor the greatest number of times it occurs in either 2 or 2000=2⋅2⋅2⋅2⋅5⋅5⋅5
Multiply the numbers: 2⋅2⋅2⋅2⋅5⋅5⋅5=2000=2000
Adjust Fractions based on the LCM
Multiply each numerator by the same amount needed to multiply its
corresponding denominator to turn it into the LCM 2000
For 21​:multiply the denominator and numerator by 100021​=2⋅10001⋅1000​=20001000​
=20001000​−20001​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=20001000−1​
Subtract the numbers: 1000−1=999=2000999​
=2000999​
=2000999​

Popular Examples

(5)+(-2)+4+6+(-7)-{(-4)+(-2)-3}+4-3+(2-4)× 11+(-2)(3-2-8)/(3-8)9^3\div 6^5

Frequently Asked Questions (FAQ)

  • What is 1× (1\div 2)-(1\div 2)\div 1000 ?

    The solution to 1× (1\div 2)-(1\div 2)\div 1000 is 999/2000

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