What is (91+199)\div 17-2× (4+3)+1 ?

The solution to (91+199)\div 17-2× (4+3)+1 is 4 1/17

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Popular Pre Algebra >

(91+199)\div 17-2× (4+3)+1

Solution

(91 + 199) \div 17 - 2 \times (4 + 3) + 1

Solution

4 \frac{1}{17}

Decimal

4.05882 \dots

Solution steps

(91 + 199) \div 17 - 2 \times (4 + 3) + 1

Follow the PEMDAS order of operations

Calculate within parentheses

(91 + 199) : 290

91 + 199

91 + 199 = 290

= 290

= 290 \div 17 - 2 \times (4 + 3) + 1

Calculate within parentheses

(4 + 3) : 7

4 + 3

4 + 3 = 7

= 7

= 290 \div 17 - 2 \times 7 + 1

Multiply and divide (left to right)

290 \div 17 : \frac{290}{17}

290 \div 17

290 \div 17 = \frac{290}{17}

= \frac{290}{17}

= \frac{290}{17} - 2 \times 7 + 1

Multiply and divide (left to right)

2 \times 7 : 14

2 \times 7

2 \times 7 = 14

= 14

= \frac{290}{17} - 14 + 1

Add and subtract (left to right)

\frac{290}{17} - 14 + 1 : \frac{69}{17}

\frac{290}{17} - 14 + 1

\frac{290}{17} - 14 = \frac{52}{17}

\frac{290}{17} - 14

Convert element to fraction:

14 = \frac{14 \cdot 17}{17}

= - \frac{14 \cdot 17}{17} + \frac{290}{17}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 14 \cdot 17 + 290}{17}

- 14 \cdot 17 + 290 = 52

- 14 \cdot 17 + 290

Multiply the numbers:

14 \cdot 17 = 238

= - 238 + 290

Add/Subtract the numbers:

- 238 + 290 = 52

= 52

= \frac{52}{17}

= \frac{52}{17} + 1

\frac{52}{17} + 1 = \frac{69}{17}

\frac{52}{17} + 1

Convert element to fraction:

1 = \frac{1 \cdot 17}{17}

= \frac{1 \cdot 17}{17} + \frac{52}{17}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 17 + 52}{17}

1 \cdot 17 + 52 = 69

1 \cdot 17 + 52

Multiply the numbers:

1 \cdot 17 = 17

= 17 + 52

Add the numbers:

17 + 52 = 69

= 69

= \frac{69}{17}

= \frac{69}{17}

= \frac{69}{17}

Convert improper fractions to mixed numbers:

\frac{69}{17} = 4 \frac{1}{17}

\frac{69}{17} = 4

Remainder

1

\frac{69}{17}

Write the problem in long division format

17 \overline{∣ 69}

Divide

69

17

to get

4

Divide

69

17

to get

4

4 17 \overline{∣ 69}

Multiply the quotient digit

(4)

by the divisor

17

4 17 \overline{∣ 69} \underline{68}

Subtract

68

from

69

4 17 \overline{∣ 69} \underline{68} 1

4 17 \overline{∣ 69} \underline{68} 1

The solution for Long Division of

\frac{69}{17}

4

with remainder of

1

4 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{69}{17} = 4 \frac{1}{17}

= 4 \frac{1}{17}

= 4 \frac{1}{17}

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Frequently Asked Questions (FAQ)

What is (91+199)\div 17-2× (4+3)+1 ?
The solution to (91+199)\div 17-2× (4+3)+1 is 4 1/17

(91+199)\div 17-2× (4+3)+1

Solution

Solution

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Frequently Asked Questions (FAQ)

What is (91+199)\div 17-2× (4+3)+1 ?

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