What is 2(-4)^2+(-4)-15 ?

The solution to 2(-4)^2+(-4)-15 is 13

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2(-4)^2+(-4)-15

2 (- 4)^{2} + (- 4) - 15

13

Solution steps

2 (- 4)^{2} + (- 4) - 15

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 2 \cdot 16 + (- 4) - 15

Multiply and divide (left to right)

2 \cdot 16 : 32

2 \cdot 16

2 \cdot 16 = 32

= 32

= 32 + (- 4) - 15

Add and subtract (left to right)

32 + (- 4) - 15 : 13

32 + (- 4) - 15

Apply rule

+ (- a) = - a

+ (- 4) = - 4

= 32 - 4 - 15

32 - 4 = 28

= 28 - 15

28 - 15 = 13

= 13

= 13

7 - 6 + 4

(8 - 1)^{2}

(1 - 2)^{2} + 1

(- 8) \times (- 5) \times (- 3)

8 \times (6 + 12 \times 2 + 10)