zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的初等代数 >

72/8+3-4(2/9)-8+6+4

解答

\frac{72}{8} + 3 - 4 (\frac{2}{9}) - 8 + 6 + 4

解答

13 \frac{1}{9}

+1

十进制

13.11111 \dots

求解步骤

\frac{72}{8} + 3 - 4 (\frac{2}{9}) - 8 + 6 + 4

\frac{72}{8} = 9

数字相除:

\frac{72}{8} = 9

9

= 9 + 3 - 4 \cdot \frac{2}{9} - 8 + 6 + 4

遵循 PEMDAS 运算顺序

乘除（左右）

4 \cdot \frac{2}{9} : \frac{8}{9}

4 \cdot \frac{2}{9}

将项转换为分式:

4 = \frac{4}{1}

= \frac{4}{1} \cdot \frac{2}{9}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 2}{1 \cdot 9}

数字相乘:

4 \cdot 2 = 8

= \frac{8}{1 \cdot 9}

数字相乘:

1 \cdot 9 = 9

= \frac{8}{9}

= 9 + 3 - \frac{8}{9} - 8 + 6 + 4

加减（左右）

9 + 3 - \frac{8}{9} - 8 + 6 + 4 : \frac{118}{9}

9 + 3 - \frac{8}{9} - 8 + 6 + 4

9 + 3 = 12

= 12 - \frac{8}{9} - 8 + 6 + 4

12 - \frac{8}{9} = \frac{100}{9}

12 - \frac{8}{9}

将项转换为分式:

12 = \frac{12 \cdot 9}{9}

= \frac{12 \cdot 9}{9} - \frac{8}{9}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{12 \cdot 9 - 8}{9}

12 \cdot 9 - 8 = 100

12 \cdot 9 - 8

数字相乘:

12 \cdot 9 = 108

= 108 - 8

数字相减:

108 - 8 = 100

= 100

= \frac{100}{9}

= \frac{100}{9} - 8 + 6 + 4

\frac{100}{9} - 8 = \frac{28}{9}

\frac{100}{9} - 8

将项转换为分式:

8 = \frac{8 \cdot 9}{9}

= - \frac{8 \cdot 9}{9} + \frac{100}{9}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 8 \cdot 9 + 100}{9}

- 8 \cdot 9 + 100 = 28

- 8 \cdot 9 + 100

数字相乘:

8 \cdot 9 = 72

= - 72 + 100

数字相加/相减:

- 72 + 100 = 28

= 28

= \frac{28}{9}

= \frac{28}{9} + 6 + 4

\frac{28}{9} + 6 = \frac{82}{9}

\frac{28}{9} + 6

将项转换为分式:

6 = \frac{6 \cdot 9}{9}

= \frac{6 \cdot 9}{9} + \frac{28}{9}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{6 \cdot 9 + 28}{9}

6 \cdot 9 + 28 = 82

6 \cdot 9 + 28

数字相乘:

6 \cdot 9 = 54

= 54 + 28

数字相加:

54 + 28 = 82

= 82

= \frac{82}{9}

= \frac{82}{9} + 4

\frac{82}{9} + 4 = \frac{118}{9}

\frac{82}{9} + 4

将项转换为分式:

4 = \frac{4 \cdot 9}{9}

= \frac{4 \cdot 9}{9} + \frac{82}{9}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 9 + 82}{9}

4 \cdot 9 + 82 = 118

4 \cdot 9 + 82

数字相乘:

4 \cdot 9 = 36

= 36 + 82

数字相加:

36 + 82 = 118

= 118

= \frac{118}{9}

= \frac{118}{9}

= \frac{118}{9}

将假分式转换为带分数:

\frac{118}{9} = 13 \frac{1}{9}

\frac{118}{9} = 13

余数

1

\frac{118}{9}

将问题写为长除法形式

9 \overline{∣ 118}

将

11

除以

9

以得到

1

将

11

除以

9

以得到

1

1 9 \overline{∣ 118}

将商数

(1)

乘以除数

9

1 9 \overline{∣ 118} \underline{9}

从

11

减去

9

1 9 \overline{∣ 118} \underline{9} 2

将被除数的下一个数字落下

1 9 \overline{∣ 118} \underline{9} 28

1 9 \overline{∣ 118} \underline{9} 28

将

28

除以

9

以得到

3

将

28

除以

9

以得到

3

13 9 \overline{∣ 118} \underline{9} 28

将商数

(3)

乘以除数

9

13 9 \overline{∣ 118} \underline{9} 28 \underline{27}

从

28

减去

27

13 9 \overline{∣ 118} \underline{9} 28 \underline{27} 1

13 9 \overline{∣ 118} \underline{9} 28 \underline{27} 1

长除

\frac{118}{9}

的解是

13

，余数是

1

13 余数 1

转换为带分数: 商

\frac{余数}{除数}

\frac{118}{9} = 13 \frac{1}{9}

= 13 \frac{1}{9}

= 13 \frac{1}{9}

流行的例子

6 (- 1) + 3

(11+22-9)\div (6-3)

(11 + 22 - 9) \div (6 - 3)

10-12+3(-15)-21\div 7

10 - 12 + 3 (- 15) - 21 \div 7

- (- 2 - 6)

(1025-8× 125)\div 5

(1025 - 8 \times 125) \div 5