What is (2^3-3)\div (-5)+(3-5)^2 ?

The solution to (2^3-3)\div (-5)+(3-5)^2 is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2^3-3)\div (-5)+(3-5)^2

(2^{3} - 3) \div (- 5) + (3 - 5)^{2}

3

Solution steps

(2^{3} - 3) \div (- 5) + (3 - 5)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(2^{3} - 3) : 5

2^{3} - 3

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 - 3

Add and subtract (left to right)

8 - 3 : 5

8 - 3

8 - 3 = 5

= 5

= 5

= 5 \div (- 5) + (3 - 5)^{2}

Calculate within parentheses

(3 - 5) : - 2

3 - 5

3 - 5 = - 2

= - 2

= 5 \div (- 5) + (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 5 \div (- 5) + 4

Multiply and divide (left to right)

5 \div (- 5) : - 1

5 \div (- 5)

Apply rule

a \div (- b) = - a \div b

5 \div (- 5) = - 5 \div 5 = - 1

= - 1

= - 1 + 4

Add and subtract (left to right)

- 1 + 4 : 3

- 1 + 4

- 1 + 4 = 3

= 3

= 3

5 \times 2 + 1

- 9 (2) + 1

5 \times 2 - 3

(- 2)^{3} - 3 (- 2) + 2

10 \div 2 + 8 \div 4 - 2 \div 7

What is (2^3-3)\div (-5)+(3-5)^2 ?
The solution to (2^3-3)\div (-5)+(3-5)^2 is 3