What is (18\times 1-20)^2 ?

The solution to (18\times 1-20)^2 is 4

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(18\times 1-20)^2

(18 \cdot 1 - 20)^{2}

4

Solution steps

(18 \cdot 1 - 20)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(18 \cdot 1 - 20) : - 2

18 \cdot 1 - 20

Multiply and divide (left to right)

18 \cdot 1 : 18

18 \cdot 1

18 \cdot 1 = 18

= 18

= 18 - 20

Add and subtract (left to right)

18 - 20 : - 2

18 - 20

18 - 20 = - 2

= - 2

= - 2

= (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4

(- 12) + (- 5 - 1 + 6)

12 \times 6 + 3 - 8 \times 4 (8 + 2)

(7 + 8 - 13 - 1)^{10} \div (16 - 8 - 7)^{5}

4^{3} \div 8

17 - 2^{3}