What is (1)^2-4(1)+3 ?

The solution to (1)^2-4(1)+3 is 0

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(1)^2-4(1)+3

(1)^{2} - 4 (1) + 3

0

Solution steps

(1)^{2} - 4 (1) + 3

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 1 - 4 (1) + 3

Multiply and divide (left to right)

4 (1) : 4

4 (1)

Apply rule:

(a) = a

(1) = 1

= 4 \cdot 1

Multiply the numbers:

4 \cdot 1 = 4

= 4

= 1 - 4 + 3

Add and subtract (left to right)

1 - 4 + 3 : 0

1 - 4 + 3

1 - 4 = - 3

= - 3 + 3

- 3 + 3 = 0

= 0

= 0

7 - (- 19) - 18 + (- 19) + 18

8^{2} - (2 \cdot 9 + 5^{2})

- 6 \times 8 \div 16

- [- (- 16) + 10]

\frac{5 \times 8 + 2}{3}