What is 6(3)^2-24(3)+18 ?

The solution to 6(3)^2-24(3)+18 is 0

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6(3)^2-24(3)+18

6 (3)^{2} - 24 (3) + 18

0

Solution steps

6 (3)^{2} - 24 (3) + 18

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 6 \cdot 9 - 24 (3) + 18

Multiply and divide (left to right)

6 \cdot 9 : 54

6 \cdot 9

6 \cdot 9 = 54

= 54

= 54 - 24 (3) + 18

Multiply and divide (left to right)

24 (3) : 72

24 (3)

Apply rule:

(a) = a

(3) = 3

= 24 \cdot 3

Multiply the numbers:

24 \cdot 3 = 72

= 72

= 54 - 72 + 18

Add and subtract (left to right)

54 - 72 + 18 : 0

54 - 72 + 18

54 - 72 = - 18

= - 18 + 18

- 18 + 18 = 0

= 0

= 0

(+ 3) + (- 4) + (- 5)

4 (10) + 2 (4)

(2 \cdot 3 \cdot 4)^{2}

2 - 2 + 4

2 - 3 + 4