What is (-4)^2+6(-4) ?

The solution to (-4)^2+6(-4) is -8

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(-4)^2+6(-4)

(- 4)^{2} + 6 (- 4)

- 8

Solution steps

(- 4)^{2} + 6 (- 4)

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 + 6 (- 4)

Multiply and divide (left to right)

6 (- 4) : - 24

6 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 4) = - 6 \cdot 4 = - 24

= - 24

= 16 - 24

Add and subtract (left to right)

16 - 24 : - 8

16 - 24

16 - 24 = - 8

= - 8

= - 8

- 4 - 3 + 10

- 4 (6) 2 + 68 (6) + 160

[36 \div (- 4) - 3 \times 2] \div (- 2 - 4 + 1)

2 (4 (7 + 4 (5 (3) - 9)) - 3 (40 - 8))

\frac{3 ( 1 - 2 ^{7} )}{1 - 2}