What is (1-1/6)\times 1/5 ?

The solution to (1-1/6)\times 1/5 is 1/6

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(1-1/6)\times 1/5

(1 - \frac{1}{6}) \cdot \frac{1}{5}

\frac{1}{6}

Solution steps

(1 - \frac{1}{6}) \frac{1}{5}

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{1}{6}) : \frac{5}{6}

1 - \frac{1}{6}

1 - \frac{1}{6} = \frac{5}{6}

1 - \frac{1}{6}

Convert element to fraction:

1 = \frac{1 \cdot 6}{6}

= \frac{1 \cdot 6}{6} - \frac{1}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 6 - 1}{6}

1 \cdot 6 - 1 = 5

1 \cdot 6 - 1

Multiply the numbers:

1 \cdot 6 = 6

= 6 - 1

Subtract the numbers:

6 - 1 = 5

= 5

= \frac{5}{6}

= \frac{5}{6}

= \frac{5}{6} \cdot \frac{1}{5}

Multiply and divide (left to right)

\frac{5}{6} \cdot \frac{1}{5} : \frac{1}{6}

\frac{5}{6} \cdot \frac{1}{5}

\frac{5}{6} \cdot \frac{1}{5} = \frac{1}{6}

= \frac{1}{6}

= \frac{1}{6}

\frac{4 ( 3 ) ^{3}}{3}

2 (2) - (2)^{2}

- (1)^{2} + 4

- (1)^{2} - 1

- (1)^{2} - 2