What is (-2)^4+(-9)^0-(-3)^2 ?

The solution to (-2)^4+(-9)^0-(-3)^2 is 8

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(-2)^4+(-9)^0-(-3)^2

(- 2)^{4} + (- 9)^{0} - (- 3)^{2}

8

Solution steps

(- 2)^{4} + (- 9)^{0} - (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= 16 + (- 9)^{0} - (- 3)^{2}

Calculate exponents

(- 9)^{0} : 1

(- 9)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 9)^{0} = 9^{0} = 1

= 1

= 16 + 1 - (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 16 + 1 - 9

Add and subtract (left to right)

16 + 1 - 9 : 8

16 + 1 - 9

16 + 1 = 17

= 17 - 9

17 - 9 = 8

= 8

= 8

16 \div 2 - 4^{2} - (- 3)^{2}

\frac{- 16 - ( - 8 ) ( - 20 )}{( - 11 ) ( - 8 )}

4 + 2 [5 + 3 (6 + 2)]

\frac{1}{5} + \frac{3}{8}

- 3 - 5 + 7 + 7