What is (-7)^2+10(-7)+21 ?

The solution to (-7)^2+10(-7)+21 is 0

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(-7)^2+10(-7)+21

(- 7)^{2} + 10 (- 7) + 21

0

Solution steps

(- 7)^{2} + 10 (- 7) + 21

Follow the PEMDAS order of operations

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 49 + 10 (- 7) + 21

Multiply and divide (left to right)

10 (- 7) : - 70

10 (- 7)

Apply rule

a \cdot (- b) = - a \cdot b

10 (- 7) = - 10 \cdot 7 = - 70

= - 70

= 49 - 70 + 21

Add and subtract (left to right)

49 - 70 + 21 : 0

49 - 70 + 21

49 - 70 = - 21

= - 21 + 21

- 21 + 21 = 0

= 0

= 0

8 - 6 \cdot 4 + 10 \div 2

3 - 2 - 6

8 \times 5 + 8

\frac{6}{3 ( 2 + 1 )}

8 \times 5 + 4