What is 5(3-5)^2+10 ?

The solution to 5(3-5)^2+10 is 30

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5(3-5)^2+10

5 (3 - 5)^{2} + 10

30

Solution steps

5 (3 - 5)^{2} + 10

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 5) : - 2

3 - 5

3 - 5 = - 2

= - 2

= 5 (- 2)^{2} + 10

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 5 \cdot 4 + 10

Multiply and divide (left to right)

5 \cdot 4 : 20

5 \cdot 4

5 \cdot 4 = 20

= 20

= 20 + 10

Add and subtract (left to right)

20 + 10 : 30

20 + 10

20 + 10 = 30

= 30

= 30

15 - (- 9) + (- 8)

8 + 72 \div 8

\frac{20}{4} \cdot (- 2) - 8

(- 3) + (+ 2) + (- 6) + (+ 5)

(7 - 2)^{2} + 5 (4)