What is 3\times (-3/2)+1 ?

The solution to 3\times (-3/2)+1 is -7/2

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3\times (-3/2)+1

3 \cdot (- \frac{3}{2}) + 1

- \frac{7}{2}

Solution steps

3 (- \frac{3}{2}) + 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

3 (- \frac{3}{2}) : - \frac{9}{2}

3 (- \frac{3}{2})

Apply rule

a \cdot (- b) = - a \cdot b

3 (- \frac{3}{2}) = - 3 \cdot \frac{3}{2}

Convert element to fraction:

3 = \frac{3}{1}

= - \frac{3}{1} \cdot \frac{3}{2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{3}{1} \cdot \frac{3}{2} = \frac{3 \cdot 3}{1 \cdot 2}

= - \frac{3 \cdot 3}{1 \cdot 2}

Multiply the numbers:

3 \cdot 3 = 9

= - \frac{9}{1 \cdot 2}

Multiply the numbers:

1 \cdot 2 = 2

= - \frac{9}{2}

= - \frac{9}{2} + 1

Add and subtract (left to right)

- \frac{9}{2} + 1 : - \frac{7}{2}

- \frac{9}{2} + 1

- \frac{9}{2} + 1 = - \frac{7}{2}

- \frac{9}{2} + 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} - \frac{9}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 - 9}{2}

1 \cdot 2 - 9 = - 7

1 \cdot 2 - 9

Multiply the numbers:

1 \cdot 2 = 2

= 2 - 9

Subtract the numbers:

2 - 9 = - 7

= - 7

= \frac{- 7}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{7}{2}

= - \frac{7}{2}

= - \frac{7}{2}

- 3 (4 - 5)^{2} - 1

5^{2} - 8 (5) + 15

4 (5)^{4}

(- 2)^{2} + 6

4 (5)^{1}