What is -1(-1-3)^2(-1+1) ?

The solution to -1(-1-3)^2(-1+1) is 0

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-1(-1-3)^2(-1+1)

- 1 (- 1 - 3)^{2} (- 1 + 1)

0

Solution steps

- 1 \cdot (- 1 - 3)^{2} (- 1 + 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 1 - 3) : - 4

- 1 - 3

- 1 - 3 = - 4

= - 4

= - 1 \cdot (- 4)^{2} (- 1 + 1)

Calculate within parentheses

(- 1 + 1) : 0

- 1 + 1

- 1 + 1 = 0

= 0

= - 1 \cdot (- 4)^{2} \cdot 0

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 1 \cdot 16 \cdot 0

Multiply and divide (left to right)

- 1 \cdot 16 \cdot 0 : 0

- 1 \cdot 16 \cdot 0

- 1 \cdot 16 = - 16

= - 16 \cdot 0

- 16 \cdot 0 = 0

= 0

= 0

13 + (- 1) + 19 + (- 20)

(2 + 8) + 8

(6 - \frac{1}{6}) \times 1

4 (- 3)^{4}

10 - 7 \times (- 2) + 12 \div (4 + 1 \times 2)