What is 2(3)^2-4(3)-6 ?

The solution to 2(3)^2-4(3)-6 is 0

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2(3)^2-4(3)-6

2 (3)^{2} - 4 (3) - 6

0

Solution steps

2 (3)^{2} - 4 (3) - 6

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 2 \cdot 9 - 4 (3) - 6

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= 18 - 4 (3) - 6

Multiply and divide (left to right)

4 (3) : 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 18 - 12 - 6

Add and subtract (left to right)

18 - 12 - 6 : 0

18 - 12 - 6

18 - 12 = 6

= 6 - 6

6 - 6 = 0

= 0

= 0

120 - (24 \div 4 + [25 + (2 \times 9) - 7 \times 4])

[5 - 2 (4 \times 5 \div 2) + 6]

3^{3} - 6^{2} + 7^{2} + 8^{2}

3 (12 - \frac{31}{4}) - \frac{31}{4}

1 0^{2} + (- 4)^{3}