What is 17%3*2-12+15 ?

The solution to 17%3*2-12+15 is 4 1/50

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Popular Pre Algebra >

17%3*2-12+15

Solution

17%3 \cdot 2 - 12 + 15

Solution

4 \frac{1}{50}

Decimal

4.02

Solution steps

17% \cdot 3 \cdot 2 - 12 + 15

Follow the PEMDAS order of operations

Multiply and divide (left to right)

17% \cdot 3 \cdot 2 : \frac{51}{50}

17% \cdot 3 \cdot 2

17%3 = \frac{51}{100}

17% \cdot 3

Convert

17%

into a fraction:

\frac{17}{100}

17%

Rewrite

17%

\frac{17}{100}

= \frac{17}{100}

= \frac{17}{100} \cdot 3

\frac{17}{100} \cdot 3 = \frac{51}{100}

\frac{17}{100} \cdot 3

Convert element to fraction:

3 = \frac{3}{1}

= \frac{17}{100} \cdot \frac{3}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{17 \cdot 3}{100 \cdot 1}

Multiply the numbers:

17 \cdot 3 = 51

= \frac{51}{100 \cdot 1}

Multiply the numbers:

100 \cdot 1 = 100

= \frac{51}{100}

= \frac{51}{100}

= \frac{51}{100} \cdot 2

\frac{51}{100} \cdot 2 = \frac{51}{50}

\frac{51}{100} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= \frac{51}{100} \cdot \frac{2}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{51 \cdot 2}{100 \cdot 1}

\frac{51 \cdot 2}{100 \cdot 1} = \frac{51}{50}

\frac{51 \cdot 2}{100 \cdot 1}

Multiply the numbers:

100 \cdot 1 = 100

= \frac{51 \cdot 2}{100}

Factor the number:

100 = 2 \cdot 50

= \frac{51 \cdot 2}{2 \cdot 50}

Cancel the common factor:

2

= \frac{51}{50}

= \frac{51}{50}

= \frac{51}{50}

= \frac{51}{50} - 12 + 15

Add and subtract (left to right)

\frac{51}{50} - 12 + 15 : \frac{201}{50}

\frac{51}{50} - 12 + 15

\frac{51}{50} - 12 = - \frac{549}{50}

\frac{51}{50} - 12

Convert element to fraction:

12 = \frac{12 \cdot 50}{50}

= - \frac{12 \cdot 50}{50} + \frac{51}{50}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 12 \cdot 50 + 51}{50}

- 12 \cdot 50 + 51 = - 549

- 12 \cdot 50 + 51

Multiply the numbers:

12 \cdot 50 = 600

= - 600 + 51

Add/Subtract the numbers:

- 600 + 51 = - 549

= - 549

= \frac{- 549}{50}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{549}{50}

= - \frac{549}{50} + 15

- \frac{549}{50} + 15 = \frac{201}{50}

- \frac{549}{50} + 15

Convert element to fraction:

15 = \frac{15 \cdot 50}{50}

= \frac{15 \cdot 50}{50} - \frac{549}{50}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{15 \cdot 50 - 549}{50}

15 \cdot 50 - 549 = 201

15 \cdot 50 - 549

Multiply the numbers:

15 \cdot 50 = 750

= 750 - 549

Subtract the numbers:

750 - 549 = 201

= 201

= \frac{201}{50}

= \frac{201}{50}

= \frac{201}{50}

Convert improper fractions to mixed numbers:

\frac{201}{50} = 4 \frac{1}{50}

\frac{201}{50} = 4

Remainder

1

\frac{201}{50}

Write the problem in long division format

50 \overline{∣ 201}

Divide

201

50

to get

4

Divide

201

50

to get

4

4 50 \overline{∣ 201}

Multiply the quotient digit

(4)

by the divisor

50

4 50 \overline{∣ 201} \underline{200}

Subtract

200

from

201

4 50 \overline{∣ 201} \underline{200} 1

4 50 \overline{∣ 201} \underline{200} 1

The solution for Long Division of

\frac{201}{50}

4

with remainder of

1

4 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{201}{50} = 4 \frac{1}{50}

= 4 \frac{1}{50}

= 4 \frac{1}{50}

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Frequently Asked Questions (FAQ)

What is 17%3*2-12+15 ?
The solution to 17%3*2-12+15 is 4 1/50

17%3*2-12+15

Solution

Solution

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Frequently Asked Questions (FAQ)

What is 17%3*2-12+15 ?

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