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受欢迎的初等代数 >

2 2/5 (-1-2 2/5)

解答

2 \frac{2}{5} (- 1 - 2 \frac{2}{5})

解答

- \frac{204}{25}

+1

十进制

- 8.16

求解步骤

2 \frac{2}{5} (- 1 - 2 \frac{2}{5})

将带分数转换为假分式:

2 \frac{2}{5} = \frac{12}{5}

2 \frac{2}{5}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{2}{5} = \frac{2 \cdot 5 + 2}{5}

= \frac{12}{5}

= \frac{12}{5} (- 1 - 2 \frac{2}{5})

将带分数转换为假分式:

2 \frac{2}{5} = \frac{12}{5}

2 \frac{2}{5}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{2}{5} = \frac{2 \cdot 5 + 2}{5}

= \frac{12}{5}

= \frac{12}{5} (- 1 - \frac{12}{5})

遵循 PEMDAS 运算顺序

计算括号内的值

(- 1 - \frac{12}{5}) : - \frac{17}{5}

- 1 - \frac{12}{5}

- 1 - \frac{12}{5} = - \frac{17}{5}

= - \frac{17}{5}

= \frac{12}{5} (- \frac{17}{5})

乘除（左右）

\frac{12}{5} (- \frac{17}{5}) : - \frac{204}{25}

\frac{12}{5} (- \frac{17}{5})

使用法则

a \cdot (- b) = - a \cdot b

\frac{12}{5} (- \frac{17}{5}) = - \frac{12}{5} \cdot \frac{17}{5}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{12}{5} \cdot \frac{17}{5} = \frac{12 \cdot 17}{5 \cdot 5}

= - \frac{12 \cdot 17}{5 \cdot 5}

数字相乘:

12 \cdot 17 = 204

= - \frac{204}{5 \cdot 5}

数字相乘:

5 \cdot 5 = 25

= - \frac{204}{25}

= - \frac{204}{25}

流行的例子

5 - \frac{1}{9} + \frac{2}{3} - \frac{7}{6}

\frac{3 ^{2} + 3}{3 - 1}

20+(3× 4-(17-3× 2^2))× 2

20 + (3 \times 4 - (17 - 3 \times 2^{2})) \times 2

- 2 - (- 2 + 6) + 5

2 0^{2} - 1 7^{2}