What is -2(1\div 2)(2(1\div 2)+7) ?

The solution to -2(1\div 2)(2(1\div 2)+7) is -8

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-2(1\div 2)(2(1\div 2)+7)

- 2 (1 \div 2) (2 (1 \div 2) + 7)

- 8

Solution steps

- 2 (1 \div 2) (2 (1 \div 2) + 7)

Follow the PEMDAS order of operations

Calculate within parentheses

(1 \div 2) : \frac{1}{2}

1 \div 2

1 \div 2 = \frac{1}{2}

= \frac{1}{2}

= - 2 \cdot \frac{1}{2} (2 (1 \div 2) + 7)

Calculate within parentheses

(2 (1 \div 2) + 7) : 8

2 (1 \div 2) + 7

Calculate within parentheses

(1 \div 2) : \frac{1}{2}

1 \div 2

1 \div 2 = \frac{1}{2}

= \frac{1}{2}

= 2 \cdot \frac{1}{2} + 7

Multiply and divide (left to right)

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{1}{2}

Cross-cancel common factor:

2

= 1

= 1 + 7

Add and subtract (left to right)

1 + 7 : 8

1 + 7

1 + 7 = 8

= 8

= 8

= - 2 \cdot \frac{1}{2} \cdot 8

Multiply and divide (left to right)

- 2 \cdot \frac{1}{2} \cdot 8 : - 8

- 2 \cdot \frac{1}{2} \cdot 8

- 2 \frac{1}{2} = - 1

- 2 \cdot \frac{1}{2}

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{2}{1} \cdot \frac{1}{2}

Cross-cancel common factor:

2

= - 1

= - 1 \cdot 8

- 1 \cdot 8 = - 8

= - 8

= - 8

(- 3)^{4} - 6 (- 3) - 8

1 4^{0} + 2^{7} + 1 5^{1}

5 (\frac{1}{2} + \frac{1}{3}) + \frac{1}{6}

- (7 - 4) - 3 - (- 6 - 5 - 12) - 9

- 2^{2} + 5 (- 2) + 1

What is -2(1\div 2)(2(1\div 2)+7) ?
The solution to -2(1\div 2)(2(1\div 2)+7) is -8