What is -5(-3)^2(2)+4(-3)(2)^2-3(-3)(2) ?

The solution to -5(-3)^2(2)+4(-3)(2)^2-3(-3)(2) is -120

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-5(-3)^2(2)+4(-3)(2)^2-3(-3)(2)

- 5 (- 3)^{2} (2) + 4 (- 3) (2)^{2} - 3 (- 3) (2)

- 120

Solution steps

- 5 (- 3)^{2} (2) + 4 (- 3) (2)^{2} - 3 (- 3) (2)

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 5 \cdot 9 (2) + 4 (- 3) (2)^{2} - 3 (- 3) (2)

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= - 5 \cdot 9 (2) + 4 (- 3) \cdot 4 - 3 (- 3) (2)

Multiply and divide (left to right)

- 5 \cdot 9 (2) : - 90

- 5 \cdot 9 (2)

- 5 \cdot 9 = - 45

= - 45 (2)

- 45 (2) = - 90

- 45 (2)

Apply rule:

(a) = a

(2) = 2

= - 45 \cdot 2

Multiply the numbers:

- 45 \cdot 2 = - 90

= - 90

= - 90

= - 90 + 4 (- 3) \cdot 4 - 3 (- 3) (2)

Multiply and divide (left to right)

4 (- 3) \cdot 4 : 48

4 (- 3) \cdot 4

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 3) = - 4 \cdot 3 = - 12

= - 12 \cdot 4

12 \cdot 4 = 48

= 48

= - 90 - 48 - 3 (- 3) (2)

Multiply and divide (left to right)

3 (- 3) (2) : - 18

3 (- 3) (2)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 3) = - 3 \cdot 3 = - 9

= - 9 (2)

Apply rule

(- a) \cdot (b) = - a \cdot b

(- 9) (2) = - 9 \cdot 2 = - 18

= - 18

= - 90 - 48 - (- 18)

Add and subtract (left to right)

- 90 - 48 - (- 18) : - 120

- 90 - 48 - (- 18)

- 90 - 48 = - 138

= - 138 - (- 18)

Apply rule

- (- a) = + a

- (- 18) = + 18

= - 138 + 18

- 138 + 18 = - 120

= - 120

= - 120

75 - 25 - (5 \times 3)

(1)^{3} - (1)^{2}

63 \div 7 - 2

100 \times 5 - 2 \times 20

- (1 - 3)^{2} - 2

What is -5(-3)^2(2)+4(-3)(2)^2-3(-3)(2) ?
The solution to -5(-3)^2(2)+4(-3)(2)^2-3(-3)(2) is -120