What is the axis 2y^2-8x-24y+56=0 ?

The axis 2y^2-8x-24y+56=0 is y=6

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axis 2y^2-8x-24y+56=0

axis

2 y^{2} - 8 x - 24 y + 56 = 0

y = 6

Solution steps

2 y^{2} - 8 x - 24 y + 56 = 0

Rewrite

2 y^{2} - 8 x - 24 y + 56 = 0

in the standard form

4 \cdot 1 \cdot (x - (- 2)) = (y - 6)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 6), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 6

y = \frac{2 x ^{2} + 7 x + 12}{2}

- x^{2} + 4 x - 11

y = 5 x^{2} - 9

4 x^{2} - 24 x - 40 y - 4 = 0

x = + (y + 11)^{2} - 14