What is the axis y=-x^2+120x+1300 ?

The axis y=-x^2+120x+1300 is x=60

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axis y=-x^2+120x+1300

axis

x = 60

Solution steps

y = - x^{2} + 120 x + 1300

Rewrite

y = - x^{2} + 120 x + 1300

in the standard form

4 (- \frac{1}{4}) (y - 4900) = (x - 60)^{2}

Therefore parabola properties are:

(h, k) = (60, 4900), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 60