What is the axis y= 3/2 x^2 ?

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axis y= 3/2 x^2

axis

y = \frac{3}{2} x^{2}

x = 0

Solution steps

y = \frac{3}{2} x^{2}

Rewrite

y = \frac{3}{2} x^{2}

in the standard form:

4 \cdot \frac{1}{6} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{6}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = \frac{1}{5} x^{2} - \frac{8}{5} x + \frac{1}{5}

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

y = x^{2} - 8 x + 16

y = 4 x^{2} + 3 x - 1

y = + 2 (x - 4)^{2} + 3