What is the axis x=(y+3)(y-1) ?

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axis x=(y+3)(y-1)

axis

x = (y + 3) (y - 1)

y = - 1

Solution steps

x = (y + 3) (y - 1)

Rewrite

x = (y + 3) (y - 1)

in the standard form

4 \cdot \frac{1}{4} (x - (- 4)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 1

y^{2} = 4 \cdot 3 x - 6

x^{2} - 10 x - 24 y = - 25 - 24

y \geq x^{2} - 9

y = 4 - 5 x^{2}

y = (x - 6) (x - 5)