What is the axis y=x^2+6x+11 ?

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axis y=x^2+6x+11

axis

y = x^{2} + 6 x + 11

x = - 3

Solution steps

y = x^{2} + 6 x + 11

Rewrite

y = x^{2} + 6 x + 11

in the standard form

4 \cdot \frac{1}{4} (y - 2) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 2), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y^{2} = - 12 x

(x - 1)^{2} = 8 (y + 3)

y = 5 x^{2} + 4 x - 3

y = - x^{2} + 10

y = - x^{2} + 12