What is the axis y=(8-2x)^2 ?

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axis y=(8-2x)^2

axis

y = (8 - 2 x)^{2}

x = 4

Solution steps

y = (8 - 2 x)^{2}

Rewrite

y = (8 - 2 x)^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 0), p = \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = 7 - 6 x^{2}

x^{2} - y = 4

y = - x^{2} + 18 x - 79

y = 12 x^{2} + 8 x - 15

x^{2} + 12 x + y + 40 = 0