What is the axis y=-2x^2+x-1 ?

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axis y=-2x^2+x-1

axis

y = - 2 x^{2} + x - 1

x = \frac{1}{4}

Solution steps

y = - 2 x^{2} + x - 1

Rewrite

y = - 2 x^{2} + x - 1

in the standard form

4 (- \frac{1}{8}) (y - (- \frac{7}{8})) = (x - \frac{1}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, - \frac{7}{8}), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{1}{4}

- x^{2} - (- y) = 4

y = x^{2} + 14 x + 48

y = x^{2} - 3 x^{1}

(y - 7)^{2} = - 12 (x + 1)

x = (y + 5)^{2}