What is the axis-x^2-(-y)=4 ?

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axis-x^2-(-y)=4

axis

- x^{2} - (- y) = 4

x = 0

Solution steps

- x^{2} - (- y) = 4

Rewrite

- x^{2} - (- y) = 4

in the standard form:

4 \cdot \frac{1}{4} (y - 4) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} + 14 x + 48

y = x^{2} - 3 x^{1}

(y - 7)^{2} = - 12 (x + 1)

x = (y + 5)^{2}

y = 4 x^{2} + 6 x + 1