What is the axis (x+9)^2=-44(y-1) ?

The axis (x+9)^2=-44(y-1) is x=-9

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axis (x+9)^2=-44(y-1)

axis

(x + 9)^{2} = - 44 (y - 1)

x = - 9

Solution steps

(x + 9)^{2} = - 44 (y - 1)

Rewrite

(x + 9)^{2} = - 44 (y - 1)

in the standard form:

4 (- 11) (y - 1) = (x - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (- 9, 1), p = - 11

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 9

y = - 2 x^{2} + 12 x - 14

y = x^{2} - 5 x + 3

y = - 6 (x - 5)^{2} + 12

y = - 2 x^{2} + x - 1

- x^{2} - (- y) = 4