What is the axis y=x^2-5x ?

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axis y=x^2-5x

axis

y = x^{2} - 5 x

x = \frac{5}{2}

Solution steps

y = x^{2} - 5 x

Rewrite

y = x^{2} - 5 x

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{25}{4})) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, - \frac{25}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{2}

y = 600 - 10 x + 0.25 x^{2}

y = - 0.00004 x^{2} - 0.00105 x + 1.055

(x + 3)^{2} = 5 y - 8

x = \frac{( y - 3 ) ^{2}}{8} + 5

y = x^{2} - 42 + 10 x