What is (x^2)/(49)-(y^2)/(16)=1 ?

The solution to (x^2)/(49)-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=7,b=4

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(x^2)/(49)-(y^2)/(16)=1

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 7, b = 4

Solution steps

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 7, b = 4

y^{2} = 12 x

y^{2} - 12 x = 0

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

x^{2} + (y - 2)^{2} = 4

x^{2} - 6 x + 8 y - 31 = 0

What is (x^2)/(49)-(y^2)/(16)=1 ?
The solution to (x^2)/(49)-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=7,b=4