What is the axis y=2x^2-4x ?

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axis y=2x^2-4x

axis

y = 2 x^{2} - 4 x

x = 1

Solution steps

y = 2 x^{2} - 4 x

Rewrite

y = 2 x^{2} - 4 x

in the standard form

4 \cdot \frac{1}{8} (y - (- 2)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = 4 - (x - 1)^{2}

y = x^{2} - 10 x - 24

+ (y - 2) = 3 (x - 5)^{2}

y = (x + 2)^{4}

x = (y + 1) (2 y + 5)