What is the axis x^2+7x+10 ?

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axis x^2+7x+10

axis

x^{2} + 7 x + 10

x = - \frac{7}{2}

Solution steps

y = x^{2} + 7 x + 10

Rewrite

y = x^{2} + 7 x + 10

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{9}{4})) = (x - (- \frac{7}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{2}, - \frac{9}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{7}{2}

y^{2} - 4 y - 8 x - 12 = 0

y^{2} = 16 x - 8

y = x^{2} + 10 x - 11

x = (y + 4)^{2}

y = + x^{2} - 9