What is the axis y=6x^2-3x5 ?

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axis y=6x^2-3x5

axis

y = 6 x^{2} - 3 x 5

x = \frac{5}{4}

Solution steps

y = 6 x^{2} - 3 x \cdot 5

Rewrite

y = 6 x^{2} - 3 x \cdot 5

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{75}{8})) = (x - \frac{5}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{4}, - \frac{75}{8}), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{4}

37.2 y = x^{2}

y = - x^{2} + 6 x + 1

y = - 3 (x + 6)^{2} + 2

y = \frac{1}{2} x^{2}

y = 2 x^{2} - 4 x - 1