What is the axis (x+7)^2=5(y+3) ?

The axis (x+7)^2=5(y+3) is x=-7

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axis (x+7)^2=5(y+3)

axis

(x + 7)^{2} = 5 (y + 3)

x = - 7

Solution steps

(x + 7)^{2} = 5 (y + 3)

Rewrite

(x + 7)^{2} = 5 (y + 3)

in the standard form:

4 \cdot \frac{5}{4} (y - (- 3)) = (x - (- 7))^{2}

Therefore parabola properties are:

(h, k) = (- 7, - 3), p = \frac{5}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 7

x \leq + y^{2}

y = - x^{2} + 80 x - 700

y = \frac{1}{5} (x - 3)^{2} - 5

y = x^{2} - 2 x + 4

y = x^{2} - 16